I’m trying to pass a specific overload of std::isfinite() to a function, but GCC refuses:

0.cpp:9:24: error: no matching function for call to ‘all_of(std::array<double, 2>::const_iterator, std::array<double, 2>::const_iterator, <unresolved overloaded function type>)’
    9 |     return !std::all_of(a.begin(), a.end(), std::isfinite<double>);
      |             ~~~~~~~~~~~^~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Here’s the source:

#include <algorithm>
#include <array>
#include <cmath>

int main()
{
    auto const a = std::array<double, 2>{{0.0, 1.0}};
    return !std::all_of(a.begin(), a.end(), std::isfinite<double>);
}

Why does it consider std::isfinite<double> to be an unresolved overloaded function type, and is there a solution simpler than wrapping in a lambda function of my own? I’d prefer not to have to write [](double x){ return std::isfinite(x); } if I don’t need to.

If it matters, I see the same symptom with all the standards versions I tried -std=c++11, -std=c++17 and -std=c++23.