for the below posted code, i would like to know why:

.then(async (promisesForTS1) => {
        return await Promise.all(promisesForTS1);                                    
    })

does not get executed?

code:

    await Promise.all([
    new Promise((resolve, reject) => {
        for (let i = 0; i < bandsDataForTS1.length; i++) {
            const contents = bandsDataForTS1[i].contents;
            const promise = TIFFUtils.bandContentsToBlob(contents)
            .then(res => {
                const asBlob = res[0];
                const asURL = res[1];

                asBlobsForTS1.push(asBlob);
                asURLsForTS1.push(asURL);
            });
            promisesForTS1.push(promise);
        }
        resolve(promisesForTS1)
    })
    .then(async (promisesForTS1) => {
        return await Promise.all(promisesForTS1);                                    
    })
]);