const mysql = require('mysql2/promise');


class db {


    static async query(sql) {

        //console.log(this.pool)

        try {
            const [rows, fields] = await this.pool.query(sql); always exit in here
            return rows;
        } catch (error) {
            console.error('Error querying the database:', error);
            return { error: 'Database query failed', details: error.message };
        }
    }


    static connect() {

        const pool = mysql.createPool({
            connectionLimit: 10,
            host: process.env.DB_HOST,
            port: process.env.DB_PORT,
            user: process.env.DB_USER,
            password: process.env.DB_PASSWORD,
            database: process.env.DB_NAME,
        })
        return pool
    }
}

why my code alway exit in try catch block , I can’t understand . I thought the error would be catched in the Try Catch block , actually it was not , this confused me .