I’m now learning the C++ moving semantics and I have trouble about the code blow:

#include <iostream>
class A {
    public:
        A() { std::cout << "Default Constructorn"; }
        A(const A& other) { std::cout << "Copy Constructorn"; }
        A(A&& other) noexcept { std::cout << "Move Constructorn"; }
    
        // 仅仅是为了避免编译器优化而定义
        A& operator=(const A& other) {
            std::cout << "Copy Assignment Operatorn";
            return *this;
        }
        A& operator=(A&& other) noexcept {
            std::cout << "Move Assignment Operatorn";
            return *this;
        }
    };
    
    void func(A&& a) {
        // Do something with 'a'
    }
    
    int main() {
        A a;  // 调用默认构造函数
        func(std::move(a));  // 调用移动构造函数
        func(A());  // 直接传递右值，调用移动构造函数
        return 0;
    }

But the output is

Default Constructor
Default Constructor

I want to know why the move constructor not be called? And only two default constructor are called? The compiler is “g++ 13.2”