I have two “equivalent” programs in C and in C++ that have different outputs.
They should print step by step all the powers of a “base” between 0 and “exp”

test.c is:

    #include <stdio.h>  

    int power(int b, int e) {  
        int p = 1;  
        for (int i = 0; i < e; i++) {  
            printf("%d^%d = %dn", b, i, p);  
            p = p * b;  
        }  
        return p;  
    }  

    int main() {  
        int base = 2, exp = 3;  
        printf("%d^%d = %dn", base, exp, power(base, exp));  
        return 0;  
    }  

output:

2^0 = 1
2^1 = 2
2^2 = 4
2^3 = 8

test.cpp is:

    #include <iostream>  

    using namespace std;  

    int power(int b, int e) {  
        int p = 1;  
        for (int i = 0; i < e; i++) {  
            cout << b << "^" << i << " = " << p << endl;  
            p = p * b;  
        }  
        return p;  
    }  

    int main() {  
        int base = 2, exp = 3;  
        cout << base << "^" << exp << " = " << power(base, exp) << endl;  
        return 0;  
    }  

output:

2^3 = 2^0 = 1
2^1 = 2
2^2 = 4
8

Can anybody please tell me why does this happen?
Why does the “cout” print the first part before executing the function?
Thank you in advance