My goal is to buffer-overflow a binary written in C. That binary asks me to input a name.
After having opened the binary with Ghidra, I discovered the following code that should help me to build an exploit :

undefined8_8 main(void)

    {
      int iVar10;
      char local_99 [106];
      undefined4 local_j;
      undefined2 local_gg;
      
      setvbuf(stdin,(char *)0x0,2,0);
      setvbuf(stdout,(char *)0x0,2,0);
      setvbuf(stderr,(char *)0x0,2,0);
      local_j = 0x64726570;
      local_gg = 0x73;
      puts(&DAT_00102008);
      fgets(local_99,0x100,stdin);
      iVar10 = strcmp((char *)&local_j,"gagne");
      if (iVar10 == 0) {
        win(local_99);
      }
      else {
        puts("Bad try, try again");
      }
      return 0;
    }

I see the line iVar10 = strcmp((char *)&local_j,"gagne"); that should help. I guess this line compares the local_j variable to the string “gagne” but I’m not really sure. What’s more, local_j variable (0x64726570) corresponds to the string "perd" after little-endian transformation.
Anyway if I pass the test, I think I could buffer-overflow the binary and maybe get my flag.
The thing I don’t get is how to hack the equality in my payload ?

Here is a script I tried to build but it does obviously not work and don’t have any other ideas :

#!/usr/bin/env python
from pwn import *

con = remote("IP", Port) 

data_ = con.recv(4096)
print(data_.decode())

payload = b"gagne" + p64(0x64726570)+b"n" 

print("payload to send =>",payload)

con.send(payload) 

con.interactive() 

Have you got some ideas ?
Any help would be greatly appreciated, thanks !