This is a follow-on to my previous question.
I can’t quite work out the XSLT to do the following. I have some HTML with one or more <ul> tags. The <li> tags may contain <a> tags. I want to remove any <li> tag if it contains an anchor where the href meets a certain pattern.
Example:
<ul>
<li><a href="/some/old/path">One</a></li>
<li><a href="/other/old/path">Two</a></li>
<li><a href="/some/older/path">Three</a></li>
<li><a href="/other/older/path">Four</a></li>
</ul>
I wish to remove the <li> lines where the href contains older so the result would be:
<ul>
<li><a href="/some/old/path">One</a></li>
<li><a href="/other/old/path">Two</a></li>
</ul>
The lines I wish to remove could be in any order and scattered across multiple <ul> tags. I’m fine if I end up with an empty <ul></ul> pair (but bonus points if such a resulting empty list can be removed easily). <li> tags that do not contain an anchor or that contain a non-matching anchor should be left as-is.
I got close with the following:
<xsl:template match="li/a[contains(@href, 'older')]">
</xsl:template>
but this leaves the opening <li>:
<ul>
<li><a href="/some/old/path">One</a></li>
<li><a href="/other/old/path">Two</a></li>
<li>
<li>
</ul>
How do I get rid of the whole <li> line?
Here’s the full HTML I’m working with:
<html>
<head>
<!-- lots of stuff I don't care about -->
</head>
<body>
<div>
<!-- lots of stuff I don't care about -->
<div>
<!-- lots of stuff I don't care about -->
<div id="key_div">
<div id="ignore_this">
<!-- lots of stuff I don't care about -->
</div>
<p>More junk I don't want</p>
<p>Even more junk I don't want</p>
<h2><span class="someClass" id="someID">Header</span></h2>
<p>Stuff I want to keep</p>
<!-- A lot of stuff I want to keep -->
<p>More stuff I want to keep</p>
<ul>
<li><a href="/some/old/path">One</a></li>
<li><a href="/some/old/other">Two</a></li>
<li><a href="/some/older/path">Three</a></li>
<li><a href="/some/older/other">Four</a></li>
</ul>
<ul>
<li>Leave this as-is</li>
</ul>
</div>
<!-- lots of stuff I don't care about -->
</div>
<!-- lots of stuff I don't care about -->
</div>
</body>
</html>
And here’s the XSLT:
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="html" indent="yes" encoding="utf-8"/>
<xsl:template match="/html">
<html>
<head>
<title></title>
</head>
<body>
<xsl:apply-templates select="//div[@id='key_div']/h2"/>
</body>
</html>
</xsl:template>
<xsl:template match="h2">
<h1>
<xsl:value-of select="." />
</h1>
<xsl:apply-templates select="following-sibling::*"/>
</xsl:template>
<!-- My failed attempt to remove certain li lines -->
<xsl:template match="li/a[contains(@href, 'older')]">
</xsl:template>
<xsl:template match="@*|node()">
<xsl:copy>
<xsl:apply-templates select="@*|node()"/>
</xsl:copy>
</xsl:template>
</xsl:stylesheet>
My current result:
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8">
<title></title>
</head>
<body>
<h1>Header</h1>
<p>Stuff I want to keep</p>
<p>More stuff I want to keep</p>
<ul>
<li><a href="/some/old/path">One</a></li>
<li><a href="/some/old/other">Two</a></li>
<li>
<li>
</ul>
<ul>
<li>Leave this as-is</li>
</ul>
</body>
</html>
I just need to figure out how to remove the full <li> line for the matching hrefs.